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Is showing that the exponential dbn is the only memoryless dbn equivalent to showing that the weibull is NOT memoryless?
This seemed like a lot of work for 2 marks (the proof we did on day 1 I mean).
So there are two ways to show this for any continuous distribution.
We were leaning towards 1 but seeing as the Q was only 2 marks - we thought this was too much work?
Also - 2 isn't really possible becuase we are only given the intensity funtion of the Weibull dbn and not its actual pdf or is there another way?