Hi,

I'm doing question 3c and am struggling to work out the tP45^(HS) value for the integral of A^(HSD).

I have attached my workings for the probability. Can you please help me to see where I am wrong or explain how they got tP45^(HS) to equal 3/5(e^(-0.005t) - e^(-0.001t))Test 2 Quedtion 3c.pdf (0,3 MB)