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2016 Test 1 Q1
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Nov 16, 2020
in
BUS 3024S - Contingencies
by
Matthew Winder
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Hi, could you pleas explain how the (1-y)^-2 is obtained in the solution below.
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answered
Nov 16, 2020
by
Jiaqi
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670
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Hi
Please see the last line you attached in the second image. If you differentiate sum (y^k) you will get sum (k*y^k-1).
So sum (k*y^k-1) = first derivative of sum (y^k) = first derivative of (1-y)^-1 = - (1-y)^-2 *(-1)= (1-y) ^-2
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