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Is \(_tq_{\overset2xy} {\overset?=} \) \( _tq_{x\overset1y}\)

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asked Sep 1, 2018 in BUS 3024S - Contingencies by Faith (610 points)

Is  \(_tq_{\overset2xy} {\overset?=} \)   \( _tq_{x\overset1y}\)

1 Answer

+1 vote
answered Sep 1, 2018 by Michael (580 points)

\(_tq_{\overset2xy}\) is the probability of x dying, conditional on y dying first.

\(_tq_{x\overset1y}\) is the probability of y dying, conditional on y dying first. 

These are two different probabilities as \(_tq_{x\overset1y}\) includes the possibility that x is still alive, while both lives are dead in \(_tq_{\overset2xy}\).